Time for another classic post from the old site, while I'm at it… As we have seen in a bunch of previous posts, the notion of

*configuration space*has held a prominent place in my mathematical explorations, because, I can't emphasize enough, it's not just the geometry of things that you can directly*see*that are important; it's the use of geometric methods to model many things that is.Consider all possible straight lines in the plane (by

*straight line*I mean those that are infinitely long). This collection is a configuration space—a

*catalogue*of these lines. What does that mean? Of course, in short words, it's a manifold, and we've talked about many of those before. But it always helps to examine examples in detail to help develop familiarity. Being a manifold means we can find local parametrizations of our collection by $n$-tuples of real numbers. How do we do this for lines in the plane?

#### Finding Some Coordinates: The Slope-Intercept Equation

First off, almost anyone reading this, regardless of mathematical background, probably was drilled at one time or another on the following famous equation, called the*slope-intercept equation*:

\[

y = mx + b.

\] The variable

*m*if you recall is the slope of a line, and

*b*is the

*y-intercept*which means where the line crosses the

*y*-axis. However few people realize that what they're doing, really, is

*indexing*every non-vertical line in the plane with some

*point*in

*another*plane (called, say, the

*mb*-plane rather than the old traditional

*xy*-plane). That is, we have a correspondence between points in one abstract

*mb*-plane to the lines in the

*xy*-plane, where

*m*is the slope, and

*b*the

*y*-intercept. It doesn't get all lines, though—vertical lines have infinite slope, and you can't have a coordinate on any plane with an infinite value. That is, you have

*charted out*the space of all possible nonvertical lines with points in a

*different*plane.

Of course how would we catch the vertical lines? We chart it out using different coordinates. There's the possibility of using

*inverse slope*and

*x*-intercept, which merely means we write the equation using

*x*as a function of

*y*. In other words, all

*non-horizontal*lines are given by:

\[

x=ky + c.

\] It's essentially obtained by reflecting everything about the diagonal line

*x*=

*y*and finding the usual slope and intercept. In other words we can

*chart out*all non-horizontal lines on this new

*kc*-plane. So you could represent the collection of all lines in the plane by having two charts... an

*atlas*or

*catalogue*of all lines, with these two sheets, the

*mb*-plane and the

*kc*-plane.

*However*, note that

*most*lines in the plane—ones that are neither vertical nor horizontal, can be represented in both forms. That is, they correspond to points on

*both*sheets. So, we would say in our usual terminology that these two sheets, or charts, determine a manifold of all possible lines; we just need to check that the overlap is smooth. But let's stop to think about what that means. We can think of it as trying to

*glue together*both sheets to form just a single catalogue. The method of gluing is that we glue together the points that represent the same line in the plane. There is a nice, exact formula for the gluing, which is very simply determined: $(m,b)$ and $(k,c)$ represent the same line if and only if $y = mx + b$ and $x = ky + c$ are equations of the same line. All we have to do to convert from one to the other is solve for

*x*in terms of

*y*, that is,

*invert*the functions. So we solve

\[

y = mx + b \iff y-b = mx \iff y/m - b/m = x \iff x = (1/m) y - b/m

\] that is, if $k = 1/m$ and $c = -b/m$, then $(m,b)$ and $(k,c)$ represent the same line in the two sheets. So to "glue" the sheets together, we glue every $(m,b)$ in the

*mb*-plane to $(1/m,-m/b)$ in the

*kc*-plane. Obviously the sheets need to be made of some very stretchable material, because it is going to be awfully hard to glue points together. Actually it's pretty hard to physically do this so don't try this at home, but just try to imagine it (don't you just love thought experiments?). For example, points in the

*mb*-plane $(1,1)$, $(2,2)$, $(3,3)$, and $(4,4)$ get glued to the corresponding points $(1,-1)$, $(1/2,-1)$, $(1/3,-1)$, and $(1/4,-1)$. You glue them in a very weird way, but if you suppose for a moment, that you allow all sorts of moving, rotating, shrinking, stretching in this process (

*topological*deformations), but without tearing, creasing, or collapsing, you can preseve the "shape" of this space, and yet make it look like something more familiar. This would be our new catalogue of lines. In addition, the catalogue has an additional property: nearby points in the catalogue translate to very similar-looking lines.

#### So, What Is It?

One should wonder what kind of overall "shape" our nice spiffy catalogue has, after gluing together the two possible charts we've made for it. As it turns out, its shape is the*Möbius strip!*That's right, the classic one-sided surface (without, as it turns out, its circle-boundary).

That is to say, if you give me a point on the

*Möbius strip*, it specifies one and only one line in the plane. One would not, initially, be able see why non-orientability enters the picture. But a little interpretation is in order. First, if we take a particular line and rotate it through 180 degrees, we get the same line back. Everything in between gives every possible (finite) slope. It so happens that as far as slopes of lines is concerned, $\infty=-\infty$, and if you go "past" this single

*projective infinity,*as they call it, you go to negative slopes. In other words, if you start on a journey on rotating a line through 180 degrees, from vertical back to vertical, you come back to the same line, except with orientation reversed (because what started out as pointing up now points down).

If you fix an origin and declare that it correspond to a certain special line in the plane, and then select a "core circle" for the Möbius strip, then as you travel around this circle, the distance traveled represents rotation angle for this special line. Traveling from the origin along the core circle and making one full loop should correspond to rotating the special line by 180 degrees. If you instead move up or down on the core circle, you instead end up sliding the line along a perpendicular direction, without changing its angle. So moving up and down the strip corresponds to parallel sliding of lines, and moving around the strip along a circle corresponds to rotating a line.

#### The Derivation

The specific formula we use is \[F(m,b) = \left(\cot^{-1} m, \frac{b}{\sqrt{m^2 + 1}}\right),

\] which sends the line to the angle it makes with the $y$-axis, and its signed perpendicular distance to the origin (the sign is determined by $b$). For the other chart, \[ F(k,c) = \begin{cases}\left( \cot^{-1} \left( \frac{1}{k}\right), \dfrac{c}{\operatorname{sgn}(-k)\sqrt{k^2+1}}\right) \quad & \text{ if } k \neq 0 \\

(0,-c) & \quad \text{ if } k = 0

\end{cases}

\] We'll show how we got this in an update to this post, or perhaps a "Part 2." This can be readily checked by simply substituting the transition charts for $(m,b)$ and $(k,c)$. However, the extra case for $k=0$ here is simply gotten by taking the limit as $k$ goes to zero

*from above*in the other case. What proves that it is a Möbius strip is that, if we take the limit as $k$ goes to zero

*from below,*it will approach $(\pi,c)$ instead of $(0,-c)$. This would make it discontinuous, unless we decide to

*identify*$(\pi,c)$ with $(0,-c)$: the $c$ going to $-c$ means we take the strip at $\pi$ and flip it around to glue it to the strip at $0$ (see this post for another example of defining a Möbius strip this way). Technically, we need an infinitely wide Möbius strip for this, but we can always scrunch it down into a finite-width strip without its boundary circle (using something like arctangent). It's just that the closer you get to the edge, the quicker things go off to infinity.

The animation is an example "path" through "line space," The blue dot travels around the white circle, and the line in the plane that corresponds to it is the blue line. The red line is a reference line perpendicular to the blue one, and always passes through the origin. The distance the blue dot from the core circle (in turquoise) indicates how far from the origin that the blue and red lines intersect. Because of the "scrunching down," though, the closer to the edge of the strip we get, the more dramatic the change in distance the blue line is from the origin. Here it is again in the plane with the Möbius strip as a picture-in-picture reference:

The more general object here we are describing is closely related to the notion of

*Grassmannian manifold*, which are all $k$-dimensional subspaces in an $n$-dimensional vector space (the only difference is that Grassmannians only consider spaces through the origin).
## No comments:

## Post a Comment